Base | Representation |
---|---|
bin | 10010111011110110001… |
… | …010100111110100000001 |
3 | 11121101122120101001112022 |
4 | 102323312022213310001 |
5 | 132304334241244131 |
6 | 2433433452211225 |
7 | 163003125245522 |
oct | 22736612476401 |
9 | 4541576331468 |
10 | 1301210103041 |
11 | 4619271a9552 |
12 | 190224769b15 |
13 | 9591ba18344 |
14 | 46d9c188849 |
15 | 23caa2a937b |
hex | 12ef62a7d01 |
1301210103041 has 2 divisors, whose sum is σ = 1301210103042. Its totient is φ = 1301210103040.
The previous prime is 1301210103001. The next prime is 1301210103079. The reversal of 1301210103041 is 1403010121031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1194421666816 + 106788436225 = 1092896^2 + 326785^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301210103041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301210103001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650605051520 + 650605051521.
It is an arithmetic number, because the mean of its divisors is an integer number (650605051521).
Almost surely, 21301210103041 is an apocalyptic number.
It is an amenable number.
1301210103041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301210103041 is an equidigital number, since it uses as much as digits as its factorization.
1301210103041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1301210103041 its reverse (1403010121031), we get a palindrome (2704220224072).
The spelling of 1301210103041 in words is "one trillion, three hundred one billion, two hundred ten million, one hundred three thousand, forty-one".
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