Base | Representation |
---|---|
bin | 10010111011110110010… |
… | …010010111001101111110 |
3 | 11121101122201012011001011 |
4 | 102323312102113031332 |
5 | 132304340301212342 |
6 | 2433434003505434 |
7 | 163003151426512 |
oct | 22736622271576 |
9 | 4541581164034 |
10 | 1301212132222 |
11 | 461928365062 |
12 | 19022538827a |
13 | 9591c278b42 |
14 | 46d9c556142 |
15 | 23caa55a717 |
hex | 12ef649737e |
1301212132222 has 4 divisors (see below), whose sum is σ = 1951818198336. Its totient is φ = 650606066110.
The previous prime is 1301212132211. The next prime is 1301212132229. The reversal of 1301212132222 is 2222312121031.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×13012121322222 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1301212132193 and 1301212132202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1301212132229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325303033054 + ... + 325303033057.
It is an arithmetic number, because the mean of its divisors is an integer number (487954549584).
Almost surely, 21301212132222 is an apocalyptic number.
1301212132222 is a deficient number, since it is larger than the sum of its proper divisors (650606066114).
1301212132222 is an equidigital number, since it uses as much as digits as its factorization.
1301212132222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 650606066113.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1301212132222 its reverse (2222312121031), we get a palindrome (3523524253253).
The spelling of 1301212132222 in words is "one trillion, three hundred one billion, two hundred twelve million, one hundred thirty-two thousand, two hundred twenty-two".
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