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13012133121031 = 119901119474921
BaseRepresentation
bin1011110101011001111110…
…0100101000110000000111
31201001221120221002221100111
42331112133210220300013
53201142322034333111
643401405203253451
72512044534415162
oct275263744506007
951057527087314
1013012133121031
114167461a15150
121561a0907a287
1373506758c185
1432db0d5b6ad9
1517871e950a21
hexbd59f928c07

13012133121031 has 8 divisors (see below), whose sum is σ = 14196488131728. Its totient is φ = 11828017080000.

The previous prime is 13012133121019. The next prime is 13012133121067.

13012133121031 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13012133121031 - 217 = 13012132989959 is a prime.

It is a super-3 number, since 3×130121331210313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13012133120993 and 13012133121011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13012133121011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59628550 + ... + 59846371.

It is an arithmetic number, because the mean of its divisors is an integer number (1774561016466).

Almost surely, 213012133121031 is an apocalyptic number.

13012133121031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13012133121031 is a deficient number, since it is larger than the sum of its proper divisors (1184355010697).

13012133121031 is a wasteful number, since it uses less digits than its factorization.

13012133121031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119484833.

The product of its (nonzero) digits is 324, while the sum is 22.

It can be divided in two parts, 1301213 and 3121031, that added together give a palindrome (4422244).

The spelling of 13012133121031 in words is "thirteen trillion, twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, thirty-one".

Divisors: 1 11 9901 108911 119474921 1314224131 1182921192821 13012133121031