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13012135001 is a prime number
BaseRepresentation
bin11000001111001010…
…10110110001011001
31020120211121221112222
430013211112301121
5203122101310001
65551103113425
7640311215435
oct140745266131
936524557488
1013012135001
115578013688
1226318a2875
1312c4a60288
148b62079c5
1551254c61b
hex307956c59

13012135001 has 2 divisors, whose sum is σ = 13012135002. Its totient is φ = 13012135000.

The previous prime is 13012134979. The next prime is 13012135033. The reversal of 13012135001 is 10053121031.

13012135001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6560190025 + 6451944976 = 80995^2 + 80324^2 .

It is a cyclic number.

It is not a de Polignac number, because 13012135001 - 214 = 13012118617 is a prime.

It is not a weakly prime, because it can be changed into another prime (13012135061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506067500 + 6506067501.

It is an arithmetic number, because the mean of its divisors is an integer number (6506067501).

Almost surely, 213012135001 is an apocalyptic number.

It is an amenable number.

13012135001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13012135001 is an equidigital number, since it uses as much as digits as its factorization.

13012135001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 13012135001 its reverse (10053121031), we get a palindrome (23065256032).

The spelling of 13012135001 in words is "thirteen billion, twelve million, one hundred thirty-five thousand, one".