13012221113 has 2 divisors, whose sum is σ = 13012221114. Its totient is φ = 13012221112.

The previous prime is 13012221109. The next prime is 13012221121. The reversal of 13012221113 is 31112221031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9642650809 + 3369570304 = 98197^2 + 58048^2 .

It is an emirp because it is prime and its reverse (31112221031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13012221113 - 2² = 13012221109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13012221091 and 13012221100.

It is not a weakly prime, because it can be changed into another prime (13012221713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506110556 + 6506110557.

It is an arithmetic number, because the mean of its divisors is an integer number (6506110557).

Almost surely, 2^13012221113 is an apocalyptic number.

It is an amenable number.

13012221113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13012221113 is an equidigital number, since it uses as much as digits as its factorization.

13012221113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13012221113 its reverse (31112221031), we get a palindrome (44124442144).

The spelling of 13012221113 in words is "thirteen billion, twelve million, two hundred twenty-one thousand, one hundred thirteen".