Base | Representation |
---|---|
bin | 111100100101111100… |
… | …0110101111101100001 |
3 | 110102212102220012211102 |
4 | 1321023320311331201 |
5 | 4112442241224134 |
6 | 135435522324145 |
7 | 12254356355066 |
oct | 1711370657541 |
9 | 412772805742 |
10 | 130122211169 |
11 | 502036611a5 |
12 | 212757b9655 |
13 | c3692c4032 |
14 | 64257dcc6d |
15 | 35b895437e |
hex | 1e4be35f61 |
130122211169 has 2 divisors, whose sum is σ = 130122211170. Its totient is φ = 130122211168.
The previous prime is 130122211103. The next prime is 130122211181. The reversal of 130122211169 is 961112221031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124570173025 + 5552038144 = 352945^2 + 74512^2 .
It is a cyclic number.
It is not a de Polignac number, because 130122211169 - 212 = 130122207073 is a prime.
It is a super-2 number, since 2×1301222111692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130122211199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65061105584 + 65061105585.
It is an arithmetic number, because the mean of its divisors is an integer number (65061105585).
Almost surely, 2130122211169 is an apocalyptic number.
It is an amenable number.
130122211169 is a deficient number, since it is larger than the sum of its proper divisors (1).
130122211169 is an equidigital number, since it uses as much as digits as its factorization.
130122211169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 29.
The spelling of 130122211169 in words is "one hundred thirty billion, one hundred twenty-two million, two hundred eleven thousand, one hundred sixty-nine".
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