Base | Representation |
---|---|
bin | 11101100101100001110010… |
… | …000101111000100000010001 |
3 | 122001201120020212102121020221 |
4 | 131211201302011320200101 |
5 | 114023410323244010101 |
6 | 1140425200001033041 |
7 | 36260010331040530 |
oct | 3545416205704021 |
9 | 561646225377227 |
10 | 130122243344401 |
11 | 385085960a7190 |
12 | 12716690025781 |
13 | 577b623468a79 |
14 | 241bd43426317 |
15 | 1009ba147daa1 |
hex | 765872178811 |
130122243344401 has 16 divisors (see below), whose sum is σ = 163507733544960. Its totient is φ = 100595578240080.
The previous prime is 130122243344389. The next prime is 130122243344411. The reversal of 130122243344401 is 104443342221031.
It is not a de Polignac number, because 130122243344401 - 213 = 130122243336209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130122243344411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6653136931 + ... + 6653156488.
It is an arithmetic number, because the mean of its divisors is an integer number (10219233346560).
Almost surely, 2130122243344401 is an apocalyptic number.
130122243344401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
130122243344401 is a deficient number, since it is larger than the sum of its proper divisors (33385490200559).
130122243344401 is a wasteful number, since it uses less digits than its factorization.
130122243344401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13306293564.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 130122243344401 its reverse (104443342221031), we get a palindrome (234565585565432).
The spelling of 130122243344401 in words is "one hundred thirty trillion, one hundred twenty-two billion, two hundred forty-three million, three hundred forty-four thousand, four hundred one".
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