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130122243344411 is a prime number
BaseRepresentation
bin11101100101100001110010…
…000101111000100000011011
3122001201120020212102121021022
4131211201302011320200123
5114023410323244010121
61140425200001033055
736260010331040543
oct3545416205704033
9561646225377238
10130122243344411
11385085960a719a
121271669002578b
13577b623468a86
14241bd43426323
151009ba147daab
hex76587217881b

130122243344411 has 2 divisors, whose sum is σ = 130122243344412. Its totient is φ = 130122243344410.

The previous prime is 130122243344389. The next prime is 130122243344473. The reversal of 130122243344411 is 114443342221031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130122243344411 - 210 = 130122243343387 is a prime.

It is a super-2 number, since 2×1301222433444112 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130122243344491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65061121672205 + 65061121672206.

It is an arithmetic number, because the mean of its divisors is an integer number (65061121672206).

Almost surely, 2130122243344411 is an apocalyptic number.

130122243344411 is a deficient number, since it is larger than the sum of its proper divisors (1).

130122243344411 is an equidigital number, since it uses as much as digits as its factorization.

130122243344411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 130122243344411 its reverse (114443342221031), we get a palindrome (244565585565442).

The spelling of 130122243344411 in words is "one hundred thirty trillion, one hundred twenty-two billion, two hundred forty-three million, three hundred forty-four thousand, four hundred eleven".