Base | Representation |
---|---|
bin | 1011110101011010100110… |
… | …1101001101101010101000 |
3 | 1201001222000210000212122112 |
4 | 2331112221231031222220 |
5 | 3201143144101012134 |
6 | 43401434115341452 |
7 | 2512052000520620 |
oct | 275265155155250 |
9 | 51058023025575 |
10 | 13012303141544 |
11 | 4167539991073 |
12 | 1561a55bb1888 |
13 | 73509387a925 |
14 | 32db27dd3880 |
15 | 17872e8371ce |
hex | bd5a9b4daa8 |
13012303141544 has 32 divisors (see below), whose sum is σ = 27889074014400. Its totient is φ = 5575587889920.
The previous prime is 13012303141429. The next prime is 13012303141553. The reversal of 13012303141544 is 44514130321031.
It is a self number, because there is not a number n which added to its sum of digits gives 13012303141544.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22914002 + ... + 23475009.
It is an arithmetic number, because the mean of its divisors is an integer number (871533562950).
Almost surely, 213012303141544 is an apocalyptic number.
13012303141544 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13012303141544 is an abundant number, since it is smaller than the sum of its proper divisors (14876770872856).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13012303141544 is a wasteful number, since it uses less digits than its factorization.
13012303141544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46394033 (or 46394029 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 13012303141544 its reverse (44514130321031), we get a palindrome (57526433462575).
The spelling of 13012303141544 in words is "thirteen trillion, twelve billion, three hundred three million, one hundred forty-one thousand, five hundred forty-four".
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