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13012517737 is a prime number
BaseRepresentation
bin11000001111001101…
…10100001101101001
31020120212100101120101
430013212310031221
5203122201031422
65551115225401
7640314401332
oct140746641551
936525311511
1013012517737
11557825519a
122631a48261
1312c4b6554b
148b62a7289
155125c5c27
hex3079b4369

13012517737 has 2 divisors, whose sum is σ = 13012517738. Its totient is φ = 13012517736.

The previous prime is 13012517729. The next prime is 13012517741. The reversal of 13012517737 is 73771521031.

13012517737 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11283538176 + 1728979561 = 106224^2 + 41581^2 .

It is a cyclic number.

It is not a de Polignac number, because 13012517737 - 23 = 13012517729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13012517696 and 13012517705.

It is not a weakly prime, because it can be changed into another prime (13012517537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506258868 + 6506258869.

It is an arithmetic number, because the mean of its divisors is an integer number (6506258869).

Almost surely, 213012517737 is an apocalyptic number.

It is an amenable number.

13012517737 is a deficient number, since it is larger than the sum of its proper divisors (1).

13012517737 is an equidigital number, since it uses as much as digits as its factorization.

13012517737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30870, while the sum is 37.

The spelling of 13012517737 in words is "thirteen billion, twelve million, five hundred seventeen thousand, seven hundred thirty-seven".