Base | Representation |
---|---|
bin | 111100100110001011… |
… | …0101111001111110011 |
3 | 110102212222122100220221 |
4 | 1321030112233033303 |
5 | 4113001243013422 |
6 | 135440402313511 |
7 | 12254513105002 |
oct | 1711426571763 |
9 | 412788570827 |
10 | 130130047987 |
11 | 50208024105 |
12 | 21278358897 |
13 | c36ab090c4 |
14 | 642687cc39 |
15 | 35b94a13c7 |
hex | 1e4c5af3f3 |
130130047987 has 2 divisors, whose sum is σ = 130130047988. Its totient is φ = 130130047986.
The previous prime is 130130047939. The next prime is 130130048003. The reversal of 130130047987 is 789740031031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130130047987 - 215 = 130130015219 is a prime.
It is not a weakly prime, because it can be changed into another prime (130130047937) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65065023993 + 65065023994.
It is an arithmetic number, because the mean of its divisors is an integer number (65065023994).
Almost surely, 2130130047987 is an apocalyptic number.
130130047987 is a deficient number, since it is larger than the sum of its proper divisors (1).
130130047987 is an equidigital number, since it uses as much as digits as its factorization.
130130047987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 127008, while the sum is 43.
The spelling of 130130047987 in words is "one hundred thirty billion, one hundred thirty million, forty-seven thousand, nine hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •