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130130113131731 is a prime number
BaseRepresentation
bin11101100101101001000111…
…001010101111010011010011
3122001202022120022211012221202
4131211221013022233103103
5114024022432430203411
61140432540525541415
736260406341113106
oct3545510712572323
9561668508735852
10130130113131731
1138510964417959
121271810771486b
13577c2a8a1a66b
14241c48c6b673d
151009eb230783b
hex765a472af4d3

130130113131731 has 2 divisors, whose sum is σ = 130130113131732. Its totient is φ = 130130113131730.

The previous prime is 130130113131671. The next prime is 130130113131743. The reversal of 130130113131731 is 137131311031031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130130113131731 - 218 = 130130112869587 is a prime.

It is a super-2 number, since 2×1301301131317312 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 130130113131694 and 130130113131703.

It is not a weakly prime, because it can be changed into another prime (130130113136731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65065056565865 + 65065056565866.

It is an arithmetic number, because the mean of its divisors is an integer number (65065056565866).

Almost surely, 2130130113131731 is an apocalyptic number.

130130113131731 is a deficient number, since it is larger than the sum of its proper divisors (1).

130130113131731 is an equidigital number, since it uses as much as digits as its factorization.

130130113131731 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1701, while the sum is 29.

Adding to 130130113131731 its reverse (137131311031031), we get a palindrome (267261424162762).

The spelling of 130130113131731 in words is "one hundred thirty trillion, one hundred thirty billion, one hundred thirteen million, one hundred thirty-one thousand, seven hundred thirty-one".