13013103113 has 2 divisors, whose sum is σ = 13013103114. Its totient is φ = 13013103112.

The previous prime is 13013103109. The next prime is 13013103127. The reversal of 13013103113 is 31130131031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10791677689 + 2221425424 = 103883^2 + 47132^2 .

It is a cyclic number.

It is not a de Polignac number, because 13013103113 - 2² = 13013103109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13013103091 and 13013103100.

It is not a weakly prime, because it can be changed into another prime (13013103143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506551556 + 6506551557.

It is an arithmetic number, because the mean of its divisors is an integer number (6506551557).

Almost surely, 2^13013103113 is an apocalyptic number.

It is an amenable number.

13013103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013103113 is an equidigital number, since it uses as much as digits as its factorization.

13013103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13013103113 its reverse (31130131031), we get a palindrome (44143234144).

The spelling of 13013103113 in words is "thirteen billion, thirteen million, one hundred three thousand, one hundred thirteen".