Base | Representation |
---|---|
bin | 11101100101101010001000… |
… | …100100101001001010111011 |
3 | 122001202102101210121022211201 |
4 | 131211222020210221022323 |
5 | 114024032204333111103 |
6 | 1140433241445035031 |
7 | 36260445464102503 |
oct | 3545521044511273 |
9 | 561672353538751 |
10 | 130131210441403 |
11 | 38511377864956 |
12 | 127183730b5a77 |
13 | 577c422168922 |
14 | 241c554314a03 |
15 | 100a02880b51d |
hex | 765a889292bb |
130131210441403 has 2 divisors, whose sum is σ = 130131210441404. Its totient is φ = 130131210441402.
The previous prime is 130131210441293. The next prime is 130131210441437. The reversal of 130131210441403 is 304144012131031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130131210441403 is a prime.
It is not a weakly prime, because it can be changed into another prime (130131210441703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65065605220701 + 65065605220702.
It is an arithmetic number, because the mean of its divisors is an integer number (65065605220702).
Almost surely, 2130131210441403 is an apocalyptic number.
130131210441403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130131210441403 is an equidigital number, since it uses as much as digits as its factorization.
130131210441403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 130131210441403 its reverse (304144012131031), we get a palindrome (434275222572434).
The spelling of 130131210441403 in words is "one hundred thirty trillion, one hundred thirty-one billion, two hundred ten million, four hundred forty-one thousand, four hundred three".
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