Base | Representation |
---|---|
bin | 10010111011111100110… |
… | …011101110100111101011 |
3 | 11121101221100001202012201 |
4 | 102323330303232213223 |
5 | 132310101303321443 |
6 | 2433452512521031 |
7 | 163005650413021 |
oct | 22737463564753 |
9 | 4541840052181 |
10 | 1301321542123 |
11 | 4619840a3369 |
12 | 190255b50177 |
13 | 95938b35725 |
14 | 46daccb6711 |
15 | 23cb4e6d34d |
hex | 12efccee9eb |
1301321542123 has 2 divisors, whose sum is σ = 1301321542124. Its totient is φ = 1301321542122.
The previous prime is 1301321542099. The next prime is 1301321542141. The reversal of 1301321542123 is 3212451231031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301321542123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1301321542091 and 1301321542100.
It is not a weakly prime, because it can be changed into another prime (1301321542163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650660771061 + 650660771062.
It is an arithmetic number, because the mean of its divisors is an integer number (650660771062).
Almost surely, 21301321542123 is an apocalyptic number.
1301321542123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301321542123 is an equidigital number, since it uses as much as digits as its factorization.
1301321542123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1301321542123 its reverse (3212451231031), we get a palindrome (4513772773154).
The spelling of 1301321542123 in words is "one trillion, three hundred one billion, three hundred twenty-one million, five hundred forty-two thousand, one hundred twenty-three".
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