Base | Representation |
---|---|
bin | 1011110101011110000100… |
… | …0110001101011011010011 |
3 | 1201002001102112200011220111 |
4 | 2331113201012031123103 |
5 | 3201202100001103133 |
6 | 43402110233422151 |
7 | 2512114013446612 |
oct | 275274106153323 |
9 | 51061375604814 |
10 | 13013232441043 |
11 | 416797650558a |
12 | 156207526a957 |
13 | 7351b12624a3 |
14 | 32dbb55b9879 |
15 | 1787862001cd |
hex | bd5e118d6d3 |
13013232441043 has 2 divisors, whose sum is σ = 13013232441044. Its totient is φ = 13013232441042.
The previous prime is 13013232441019. The next prime is 13013232441103. The reversal of 13013232441043 is 34014423231031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13013232441043 is a prime.
It is a super-2 number, since 2×130132324410432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13013232440996 and 13013232441014.
It is not a weakly prime, because it can be changed into another prime (13013232441943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506616220521 + 6506616220522.
It is an arithmetic number, because the mean of its divisors is an integer number (6506616220522).
Almost surely, 213013232441043 is an apocalyptic number.
13013232441043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013232441043 is an equidigital number, since it uses as much as digits as its factorization.
13013232441043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13013232441043 its reverse (34014423231031), we get a palindrome (47027655672074).
The spelling of 13013232441043 in words is "thirteen trillion, thirteen billion, two hundred thirty-two million, four hundred forty-one thousand, forty-three".
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