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1301355123041 is a prime number
BaseRepresentation
bin10010111011111110110…
…011110101000101100001
311121102000200020211120102
4102323332303311011201
5132310133402414131
62433500112352145
7163006536014411
oct22737663650541
94542020224512
101301355123041
114619a104a196
12190265245655
1395942a925ac
1446db3538641
1523cb7da31cb
hex12efecf5161

1301355123041 has 2 divisors, whose sum is σ = 1301355123042. Its totient is φ = 1301355123040.

The previous prime is 1301355123037. The next prime is 1301355123053. The reversal of 1301355123041 is 1403215531031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1249653458641 + 51701664400 = 1117879^2 + 227380^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301355123041 - 22 = 1301355123037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1301355122995 and 1301355123013.

It is not a weakly prime, because it can be changed into another prime (1301355323041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650677561520 + 650677561521.

It is an arithmetic number, because the mean of its divisors is an integer number (650677561521).

Almost surely, 21301355123041 is an apocalyptic number.

It is an amenable number.

1301355123041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301355123041 is an equidigital number, since it uses as much as digits as its factorization.

1301355123041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 29.

The spelling of 1301355123041 in words is "one trillion, three hundred one billion, three hundred fifty-five million, one hundred twenty-three thousand, forty-one".