Base | Representation |
---|---|
bin | 11101100101110010100111… |
… | …001101001110100100011111 |
3 | 122001210021220021011212011120 |
4 | 131211302213031032210133 |
5 | 114024204330432101143 |
6 | 1140441345101022023 |
7 | 36261220210640064 |
oct | 3545624715164437 |
9 | 561707807155146 |
10 | 130140314331423 |
11 | 38515219764200 |
12 | 1271a093b54913 |
13 | 57802432c21b6 |
14 | 241cb79450c6b |
15 | 100a3acbaa383 |
hex | 765ca734e91f |
130140314331423 has 24 divisors (see below), whose sum is σ = 190730779991808. Its totient is φ = 78872204730000.
The previous prime is 130140314331421. The next prime is 130140314331481. The reversal of 130140314331423 is 324133413041031.
It is not a de Polignac number, because 130140314331423 - 21 = 130140314331421 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130140314331421) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 40062348 + ... + 43188798.
It is an arithmetic number, because the mean of its divisors is an integer number (7947115832992).
Almost surely, 2130140314331423 is an apocalyptic number.
130140314331423 is a deficient number, since it is larger than the sum of its proper divisors (60590465660385).
130140314331423 is a wasteful number, since it uses less digits than its factorization.
130140314331423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3241147 (or 3241136 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 130140314331423 its reverse (324133413041031), we get a palindrome (454273727372454).
The spelling of 130140314331423 in words is "one hundred thirty trillion, one hundred forty billion, three hundred fourteen million, three hundred thirty-one thousand, four hundred twenty-three".
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