Base | Representation |
---|---|
bin | 1011110101100001000101… |
… | …1010010010110001110011 |
3 | 1201002010112000220110111212 |
4 | 2331120101122102301303 |
5 | 3201210230002342321 |
6 | 43402322511030335 |
7 | 2512143055262063 |
oct | 275302132226163 |
9 | 51063460813455 |
10 | 13014043012211 |
11 | 416825200670a |
12 | 156226080b3ab |
13 | 7352b0176bb7 |
14 | 32dc510d73a3 |
15 | 1787d246455b |
hex | bd611692c73 |
13014043012211 has 2 divisors, whose sum is σ = 13014043012212. Its totient is φ = 13014043012210.
The previous prime is 13014043012207. The next prime is 13014043012273. The reversal of 13014043012211 is 11221034041031.
13014043012211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13014043012211 - 22 = 13014043012207 is a prime.
It is not a weakly prime, because it can be changed into another prime (13014043012291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507021506105 + 6507021506106.
It is an arithmetic number, because the mean of its divisors is an integer number (6507021506106).
Almost surely, 213014043012211 is an apocalyptic number.
13014043012211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13014043012211 is an equidigital number, since it uses as much as digits as its factorization.
13014043012211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13014043012211 its reverse (11221034041031), we get a palindrome (24235077053242).
The spelling of 13014043012211 in words is "thirteen trillion, fourteen billion, forty-three million, twelve thousand, two hundred eleven".
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