Base | Representation |
---|---|
bin | 1011110101100001001101… |
… | …1110101100111100110111 |
3 | 1201002010121110012220222021 |
4 | 2331120103132230330313 |
5 | 3201210312344104143 |
6 | 43402330151014011 |
7 | 2512143656306041 |
oct | 275302336547467 |
9 | 51063543186867 |
10 | 13014077722423 |
11 | 416826a663a38 |
12 | 156227036a307 |
13 | 7352b740aa9b |
14 | 32dc55970a91 |
15 | 1787d551dced |
hex | bd6137acf37 |
13014077722423 has 4 divisors (see below), whose sum is σ = 13040158039000. Its totient is φ = 12987997405848.
The previous prime is 13014077722411. The next prime is 13014077722433. The reversal of 13014077722423 is 32422777041031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13014077722423 - 217 = 13014077591351 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13014077722423.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13014077722433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13040157540 + ... + 13040158537.
It is an arithmetic number, because the mean of its divisors is an integer number (3260039509750).
Almost surely, 213014077722423 is an apocalyptic number.
13014077722423 is a deficient number, since it is larger than the sum of its proper divisors (26080316577).
13014077722423 is an equidigital number, since it uses as much as digits as its factorization.
13014077722423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26080316576.
The product of its (nonzero) digits is 395136, while the sum is 43.
The spelling of 13014077722423 in words is "thirteen trillion, fourteen billion, seventy-seven million, seven hundred twenty-two thousand, four hundred twenty-three".
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