Base | Representation |
---|---|
bin | 1011110101100001001101… |
… | …1110101100111101000001 |
3 | 1201002010121110012220222122 |
4 | 2331120103132230331001 |
5 | 3201210312344104213 |
6 | 43402330151014025 |
7 | 2512143656306054 |
oct | 275302336547501 |
9 | 51063543186878 |
10 | 13014077722433 |
11 | 416826a663a47 |
12 | 156227036a315 |
13 | 7352b740aaa8 |
14 | 32dc55970a9b |
15 | 1787d551dd08 |
hex | bd6137acf41 |
13014077722433 has 2 divisors, whose sum is σ = 13014077722434. Its totient is φ = 13014077722432.
The previous prime is 13014077722411. The next prime is 13014077722489. The reversal of 13014077722433 is 33422777041031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12978027865009 + 36049857424 = 3602503^2 + 189868^2 .
It is a cyclic number.
It is not a de Polignac number, because 13014077722433 - 234 = 12996897853249 is a prime.
It is not a weakly prime, because it can be changed into another prime (13014077422433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507038861216 + 6507038861217.
It is an arithmetic number, because the mean of its divisors is an integer number (6507038861217).
Almost surely, 213014077722433 is an apocalyptic number.
It is an amenable number.
13014077722433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13014077722433 is an equidigital number, since it uses as much as digits as its factorization.
13014077722433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 592704, while the sum is 44.
The spelling of 13014077722433 in words is "thirteen trillion, fourteen billion, seventy-seven million, seven hundred twenty-two thousand, four hundred thirty-three".
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