1301422112021 has 4 divisors (see below), whose sum is σ = 1302595622700. Its totient is φ = 1300248601344.

The previous prime is 1301422111993. The next prime is 1301422112051. The reversal of 1301422112021 is 1202112241031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 58932903121 + 1242489208900 = 242761^2 + 1114670^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1301422112021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301422111984 and 1301422112002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301422112051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 586753676 + ... + 586755893.

It is an arithmetic number, because the mean of its divisors is an integer number (325648905675).

Almost surely, 2^{1301422112021} is an apocalyptic number.

It is an amenable number.

1301422112021 is a deficient number, since it is larger than the sum of its proper divisors (1173510679).

1301422112021 is a wasteful number, since it uses less digits than its factorization.

1301422112021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1173510678.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1301422112021 its reverse (1202112241031), we get a palindrome (2503534353052).

The spelling of 1301422112021 in words is "one trillion, three hundred one billion, four hundred twenty-two million, one hundred twelve thousand, twenty-one".