Base | Representation |
---|---|
bin | 10010111100000010110… |
… | …011010111110100110011 |
3 | 11121102012100022020012212 |
4 | 102330002303113310303 |
5 | 132310303030041201 |
6 | 2433510504242335 |
7 | 163011311300555 |
oct | 22740263276463 |
9 | 4542170266185 |
10 | 1301422112051 |
11 | 461a25944006 |
12 | 1902837703ab |
13 | 95953918769 |
14 | 46dbc3b54d5 |
15 | 23cbdbd6abb |
hex | 12f02cd7d33 |
1301422112051 has 2 divisors, whose sum is σ = 1301422112052. Its totient is φ = 1301422112050.
The previous prime is 1301422111993. The next prime is 1301422112099. The reversal of 1301422112051 is 1502112241031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301422112051 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301422112951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650711056025 + 650711056026.
It is an arithmetic number, because the mean of its divisors is an integer number (650711056026).
Almost surely, 21301422112051 is an apocalyptic number.
1301422112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301422112051 is an equidigital number, since it uses as much as digits as its factorization.
1301422112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 1301422112051 its reverse (1502112241031), we get a palindrome (2803534353082).
The spelling of 1301422112051 in words is "one trillion, three hundred one billion, four hundred twenty-two million, one hundred twelve thousand, fifty-one".
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