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13014222100142 = 26507111050071
BaseRepresentation
bin1011110101100001110000…
…0101011101011010101110
31201002010222111220001222012
42331120130011131122232
53201211111324201032
643402352345321222
72512150361431244
oct275303405353256
951063874801865
1013014222100142
11416833410606a
1215622b0796212
1373530b2bb8a3
1432dc6abd4794
151787e303c6b2
hexbd61c15d6ae

13014222100142 has 4 divisors (see below), whose sum is σ = 19521333150216. Its totient is φ = 6507111050070.

The previous prime is 13014222100133. The next prime is 13014222100151. The reversal of 13014222100142 is 24100122241031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13014222100133) and next prime (13014222100151).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3253555525034 + ... + 3253555525037.

It is an arithmetic number, because the mean of its divisors is an integer number (4880333287554).

Almost surely, 213014222100142 is an apocalyptic number.

13014222100142 is a deficient number, since it is larger than the sum of its proper divisors (6507111050074).

13014222100142 is an equidigital number, since it uses as much as digits as its factorization.

13014222100142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6507111050073.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13014222100142 its reverse (24100122241031), we get a palindrome (37114344341173).

The spelling of 13014222100142 in words is "thirteen trillion, fourteen billion, two hundred twenty-two million, one hundred thousand, one hundred forty-two".

Divisors: 1 2 6507111050071 13014222100142