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130144323433 is a prime number
BaseRepresentation
bin111100100110100110…
…1001100011101101001
3110102220222111122011011
41321031031030131221
54113013421322213
6135442032303521
712255045332245
oct1711515143551
9412828448134
10130144323433
11502150944a3
12212810a1ba1
13c370a66a07
146428717425
1535ba87103d
hex1e4d34c769

130144323433 has 2 divisors, whose sum is σ = 130144323434. Its totient is φ = 130144323432.

The previous prime is 130144323409. The next prime is 130144323437. The reversal of 130144323433 is 334323441031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69575667984 + 60568655449 = 263772^2 + 246107^2 .

It is an emirp because it is prime and its reverse (334323441031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130144323433 - 213 = 130144315241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130144323395 and 130144323404.

It is not a weakly prime, because it can be changed into another prime (130144323437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65072161716 + 65072161717.

It is an arithmetic number, because the mean of its divisors is an integer number (65072161717).

Almost surely, 2130144323433 is an apocalyptic number.

It is an amenable number.

130144323433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130144323433 is an equidigital number, since it uses as much as digits as its factorization.

130144323433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 130144323433 its reverse (334323441031), we get a palindrome (464467764464).

The spelling of 130144323433 in words is "one hundred thirty billion, one hundred forty-four million, three hundred twenty-three thousand, four hundred thirty-three".