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130146330672257 is a prime number
BaseRepresentation
bin11101100101111000001101…
…110011101111110010000001
3122001210212102112222122020212
4131211320031303233302001
5114024304141123003012
61140444222100043505
736261522253664264
oct3545701563576201
9561725375878225
10130146330672257
1138517826836109
121271b292993595
13578099188c9a3
14241d18a4b4cdb
15100a610e6eb22
hex765e0dcefc81

130146330672257 has 2 divisors, whose sum is σ = 130146330672258. Its totient is φ = 130146330672256.

The previous prime is 130146330672229. The next prime is 130146330672283. The reversal of 130146330672257 is 752276033641031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90498101276401 + 39648229395856 = 9513049^2 + 6296684^2 .

It is an emirp because it is prime and its reverse (752276033641031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130146330672257 is a prime.

It is not a weakly prime, because it can be changed into another prime (130146330671257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65073165336128 + 65073165336129.

It is an arithmetic number, because the mean of its divisors is an integer number (65073165336129).

Almost surely, 2130146330672257 is an apocalyptic number.

It is an amenable number.

130146330672257 is a deficient number, since it is larger than the sum of its proper divisors (1).

130146330672257 is an equidigital number, since it uses as much as digits as its factorization.

130146330672257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3810240, while the sum is 50.

The spelling of 130146330672257 in words is "one hundred thirty trillion, one hundred forty-six billion, three hundred thirty million, six hundred seventy-two thousand, two hundred fifty-seven".