Base | Representation |
---|---|
bin | 10010111100001000001… |
… | …111110011101111000011 |
3 | 11121102102201011210201211 |
4 | 102330020033303233003 |
5 | 132310444420434413 |
6 | 2433523530110551 |
7 | 163013500545316 |
oct | 22741017635703 |
9 | 4542381153654 |
10 | 1301513452483 |
11 | 461a72460472 |
12 | 1902aa27b457 |
13 | 9596981985a |
14 | 46dca59097d |
15 | 23cc6c2a83d |
hex | 12f083f3bc3 |
1301513452483 has 2 divisors, whose sum is σ = 1301513452484. Its totient is φ = 1301513452482.
The previous prime is 1301513452457. The next prime is 1301513452553. The reversal of 1301513452483 is 3842543151031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1301513452483 - 25 = 1301513452451 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301513452403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650756726241 + 650756726242.
It is an arithmetic number, because the mean of its divisors is an integer number (650756726242).
Almost surely, 21301513452483 is an apocalyptic number.
1301513452483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301513452483 is an equidigital number, since it uses as much as digits as its factorization.
1301513452483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 1301513452483 in words is "one trillion, three hundred one billion, five hundred thirteen million, four hundred fifty-two thousand, four hundred eighty-three".
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