Base | Representation |
---|---|
bin | 11000001111100010… |
… | …01111010010000111 |
3 | 1020121001111012121100 |
4 | 30013301033102013 |
5 | 203123401000210 |
6 | 5551253551143 |
7 | 640346541303 |
oct | 140761172207 |
9 | 36531435540 |
10 | 13015250055 |
11 | 5579851005 |
12 | 26329454b3 |
13 | 12c55b10c2 |
14 | 8b67b8d03 |
15 | 5129655c0 |
hex | 307c4f487 |
13015250055 has 48 divisors (see below), whose sum is σ = 23549501664. Its totient is φ = 6643088640.
The previous prime is 13015250047. The next prime is 13015250069. The reversal of 13015250055 is 55005251031.
13015250055 is a `hidden beast` number, since 1 + 3 + 0 + 152 + 500 + 5 + 5 = 666.
13015250055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13015250055 - 23 = 13015250047 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 37492 + ... + 165638.
It is an arithmetic number, because the mean of its divisors is an integer number (490614618).
Almost surely, 213015250055 is an apocalyptic number.
13015250055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13015250055 is a deficient number, since it is larger than the sum of its proper divisors (10534251609).
13015250055 is a wasteful number, since it uses less digits than its factorization.
13015250055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 128256 (or 128253 counting only the distinct ones).
The product of its (nonzero) digits is 3750, while the sum is 27.
The spelling of 13015250055 in words is "thirteen billion, fifteen million, two hundred fifty thousand, fifty-five".
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