Base | Representation |
---|---|
bin | 11000001111110100… |
… | …00100001111000111 |
3 | 1020121012211202212211 |
4 | 30013322010033013 |
5 | 203124444022403 |
6 | 5551415324251 |
7 | 640405316635 |
oct | 140772041707 |
9 | 36535752784 |
10 | 13017564103 |
11 | 5580091645 |
12 | 2633680687 |
13 | 12c5c1146b |
14 | 8b6c1c355 |
15 | 512c7106d |
hex | 307e843c7 |
13017564103 has 12 divisors (see below), whose sum is σ = 13323377952. Its totient is φ = 12718613600.
The previous prime is 13017564089. The next prime is 13017564137. The reversal of 13017564103 is 30146571031.
13017564103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13017564103 - 233 = 4427629511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13017564163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1358178 + ... + 1367728.
It is an arithmetic number, because the mean of its divisors is an integer number (1110281496).
Almost surely, 213017564103 is an apocalyptic number.
13017564103 is a deficient number, since it is larger than the sum of its proper divisors (305813849).
13017564103 is an frugal number, since it uses more digits than its factorization.
13017564103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10262 (or 10215 counting only the distinct ones).
The product of its (nonzero) digits is 7560, while the sum is 31.
The spelling of 13017564103 in words is "thirteen billion, seventeen million, five hundred sixty-four thousand, one hundred three".
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