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1301791264489 is a prime number
BaseRepresentation
bin10010111100011000110…
…011100100111011101001
311121110011001221010011101
4102330120303210323221
5132312032030430424
62434011252401401
7163023413114002
oct22743063447351
94543131833141
101301791264489
114620a525a771
12190367316261
13959b2249361
144701542a1a9
1523ce1305344
hex12f18ce4ee9

1301791264489 has 2 divisors, whose sum is σ = 1301791264490. Its totient is φ = 1301791264488.

The previous prime is 1301791264447. The next prime is 1301791264537. The reversal of 1301791264489 is 9844621971031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1283133890025 + 18657374464 = 1132755^2 + 136592^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301791264489 - 217 = 1301791133417 is a prime.

It is a super-2 number, since 2×13017912644892 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1301791214489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650895632244 + 650895632245.

It is an arithmetic number, because the mean of its divisors is an integer number (650895632245).

Almost surely, 21301791264489 is an apocalyptic number.

It is an amenable number.

1301791264489 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301791264489 is an equidigital number, since it uses as much as digits as its factorization.

1301791264489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 55.

The spelling of 1301791264489 in words is "one trillion, three hundred one billion, seven hundred ninety-one million, two hundred sixty-four thousand, four hundred eighty-nine".