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130201110002233 is a prime number
BaseRepresentation
bin11101100110101011001110…
…111010010011101000111001
3122002000002211012221221002001
4131212223032322103220321
5114031203333130032413
61140525321511141001
736265501611420544
oct3546531672235071
9562002735857061
10130201110002233
1138538a87295546
1212729a20374761
135785bb18478ca
142421aa586385b
15100bc6a1cc4dd
hex766acee93a39

130201110002233 has 2 divisors, whose sum is σ = 130201110002234. Its totient is φ = 130201110002232.

The previous prime is 130201110002177. The next prime is 130201110002239. The reversal of 130201110002233 is 332200011102031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127662610268944 + 2538499733289 = 11298788^2 + 1593267^2 .

It is a cyclic number.

It is not a de Polignac number, because 130201110002233 - 221 = 130201107905081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130201110002233.

It is not a weakly prime, because it can be changed into another prime (130201110002239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100555001116 + 65100555001117.

It is an arithmetic number, because the mean of its divisors is an integer number (65100555001117).

Almost surely, 2130201110002233 is an apocalyptic number.

It is an amenable number.

130201110002233 is a deficient number, since it is larger than the sum of its proper divisors (1).

130201110002233 is an equidigital number, since it uses as much as digits as its factorization.

130201110002233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 130201110002233 its reverse (332200011102031), we get a palindrome (462401121104264).

The spelling of 130201110002233 in words is "one hundred thirty trillion, two hundred one billion, one hundred ten million, two thousand, two hundred thirty-three".