Base | Representation |
---|---|
bin | 11101100110101011010110… |
… | …101111101000010111110101 |
3 | 122002000010011101020201010221 |
4 | 131212223112233220113311 |
5 | 114031204120300440201 |
6 | 1140525342524014341 |
7 | 36265505065441531 |
oct | 3546532657502765 |
9 | 562003141221127 |
10 | 130201241421301 |
11 | 38539044496646 |
12 | 12729a583913b1 |
13 | 5785c02b3c27b |
14 | 2421ab90b2bc1 |
15 | 100bc769db4a1 |
hex | 766ad6be85f5 |
130201241421301 has 16 divisors (see below), whose sum is σ = 134424953929728. Its totient is φ = 126034971552000.
The previous prime is 130201241421299. The next prime is 130201241421313. The reversal of 130201241421301 is 103124142102031.
It is not a de Polignac number, because 130201241421301 - 21 = 130201241421299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130201241425301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14846965 + ... + 21927946.
It is an arithmetic number, because the mean of its divisors is an integer number (8401559620608).
Almost surely, 2130201241421301 is an apocalyptic number.
It is an amenable number.
130201241421301 is a deficient number, since it is larger than the sum of its proper divisors (4223712508427).
130201241421301 is a wasteful number, since it uses less digits than its factorization.
130201241421301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36775692.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 130201241421301 its reverse (103124142102031), we get a palindrome (233325383523332).
The spelling of 130201241421301 in words is "one hundred thirty trillion, two hundred one billion, two hundred forty-one million, four hundred twenty-one thousand, three hundred one".
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