Base | Representation |
---|---|
bin | 1011110101111000000100… |
… | …1111001011011011111010 |
3 | 1201002201110002220220202221 |
4 | 2331132001033023123322 |
5 | 3201310344303122132 |
6 | 43405223115114254 |
7 | 2512452020625442 |
oct | 275360117133372 |
9 | 51081402826687 |
10 | 13020214114042 |
11 | 416a929481873 |
12 | 15634a344298a |
13 | 735a5481c645 |
14 | 330278925122 |
15 | 178a440e8e97 |
hex | bd7813cb6fa |
13020214114042 has 8 divisors (see below), whose sum is σ = 19545591168000. Its totient is φ = 6505017058044.
The previous prime is 13020214114003. The next prime is 13020214114049. The reversal of 13020214114042 is 24041141202031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13020214113998 and 13020214114016.
It is not an unprimeable number, because it can be changed into a prime (13020214114049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2544996292 + ... + 2545001407.
It is an arithmetic number, because the mean of its divisors is an integer number (2443198896000).
Almost surely, 213020214114042 is an apocalyptic number.
13020214114042 is a deficient number, since it is larger than the sum of its proper divisors (6525377053958).
13020214114042 is a wasteful number, since it uses less digits than its factorization.
13020214114042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5089998980.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13020214114042 its reverse (24041141202031), we get a palindrome (37061355316073).
The spelling of 13020214114042 in words is "thirteen trillion, twenty billion, two hundred fourteen million, one hundred fourteen thousand, forty-two".
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