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1302040121 is a prime number
BaseRepresentation
bin100110110011011…
…1000111000111001
310100202000111021012
41031212320320321
510131310240441
6333111123305
744160105224
oct11546707071
93322014235
101302040121
11608a71018
12304073535
131799a0755
14c4cd25bb
15794949eb
hex4d9b8e39

1302040121 has 2 divisors, whose sum is σ = 1302040122. Its totient is φ = 1302040120.

The previous prime is 1302040099. The next prime is 1302040171. The reversal of 1302040121 is 1210402031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1300612096 + 1428025 = 36064^2 + 1195^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1302040121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1302040096 and 1302040105.

It is not a weakly prime, because it can be changed into another prime (1302040171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651020060 + 651020061.

It is an arithmetic number, because the mean of its divisors is an integer number (651020061).

Almost surely, 21302040121 is an apocalyptic number.

It is an amenable number.

1302040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302040121 is an equidigital number, since it uses as much as digits as its factorization.

1302040121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 1302040121 is about 36083.7930517289. The cubic root of 1302040121 is about 1091.9635009627.

Adding to 1302040121 its reverse (1210402031), we get a palindrome (2512442152).

The spelling of 1302040121 in words is "one billion, three hundred two million, forty thousand, one hundred twenty-one".