Base | Representation |
---|---|
bin | 11000010000001001… |
… | …11011100001100101 |
3 | 1020121102012110110200 |
4 | 30020010323201211 |
5 | 203131211141010 |
6 | 5552000341113 |
7 | 640441450566 |
oct | 141004734145 |
9 | 36542173420 |
10 | 13020412005 |
11 | 5581757287 |
12 | 2634614799 |
13 | 12c669a803 |
14 | 8b736016d |
15 | 513134cc0 |
hex | 30813b865 |
13020412005 has 48 divisors (see below), whose sum is σ = 22815342576. Its totient is φ = 6868592640.
The previous prime is 13020411977. The next prime is 13020412037. The reversal of 13020412005 is 50021402031.
It can be written as a sum of positive squares in 8 ways, for example, as 4444355556 + 8576056449 = 66666^2 + 92607^2 .
It is not a de Polignac number, because 13020412005 - 25 = 13020411973 is a prime.
It is a super-2 number, since 2×130204120052 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2748619 + ... + 2753351.
It is an arithmetic number, because the mean of its divisors is an integer number (475319637).
Almost surely, 213020412005 is an apocalyptic number.
13020412005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13020412005 is a deficient number, since it is larger than the sum of its proper divisors (9794930571).
13020412005 is a wasteful number, since it uses less digits than its factorization.
13020412005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5398 (or 5395 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 18.
Adding to 13020412005 its reverse (50021402031), we get a palindrome (63041814036).
The spelling of 13020412005 in words is "thirteen billion, twenty million, four hundred twelve thousand, five".
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