Base | Representation |
---|---|
bin | 10010111100101000100… |
… | …010100111000001010011 |
3 | 11121110211110200002000111 |
4 | 102330220202213001103 |
5 | 132313102121031201 |
6 | 2434053402502151 |
7 | 163033100014021 |
oct | 22745042470123 |
9 | 4543743602014 |
10 | 1302055252051 |
11 | 462220277504 |
12 | 19041b804957 |
13 | 95a24b48608 |
14 | 4703c507711 |
15 | 23d0959db51 |
hex | 12f288a7053 |
1302055252051 has 2 divisors, whose sum is σ = 1302055252052. Its totient is φ = 1302055252050.
The previous prime is 1302055252027. The next prime is 1302055252061. The reversal of 1302055252051 is 1502525502031.
It is a strong prime.
It is an emirp because it is prime and its reverse (1502525502031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1302055252051 - 27 = 1302055251923 is a prime.
It is not a weakly prime, because it can be changed into another prime (1302055252061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651027626025 + 651027626026.
It is an arithmetic number, because the mean of its divisors is an integer number (651027626026).
Almost surely, 21302055252051 is an apocalyptic number.
1302055252051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302055252051 is an equidigital number, since it uses as much as digits as its factorization.
1302055252051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 1302055252051 in words is "one trillion, three hundred two billion, fifty-five million, two hundred fifty-two thousand, fifty-one".
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