Base | Representation |
---|---|
bin | 1011110101111001101000… |
… | …1011110010000101111001 |
3 | 1201002202112021110221221022 |
4 | 2331132122023302011321 |
5 | 3201312223424413301 |
6 | 43405332425552225 |
7 | 2512465262306234 |
oct | 275363213620571 |
9 | 51082467427838 |
10 | 13020632654201 |
11 | 4170023760227 |
12 | 156359b645675 |
13 | 735ac0452a43 |
14 | 3302b835441b |
15 | 178a6ac20d1b |
hex | bd79a2f2179 |
13020632654201 has 2 divisors, whose sum is σ = 13020632654202. Its totient is φ = 13020632654200.
The previous prime is 13020632654153. The next prime is 13020632654233. The reversal of 13020632654201 is 10245623602031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8162791843600 + 4857840810601 = 2857060^2 + 2204051^2 .
It is a cyclic number.
It is not a de Polignac number, because 13020632654201 - 222 = 13020628459897 is a prime.
It is not a weakly prime, because it can be changed into another prime (13020632654401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510316327100 + 6510316327101.
It is an arithmetic number, because the mean of its divisors is an integer number (6510316327101).
Almost surely, 213020632654201 is an apocalyptic number.
It is an amenable number.
13020632654201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13020632654201 is an equidigital number, since it uses as much as digits as its factorization.
13020632654201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 35.
The spelling of 13020632654201 in words is "thirteen trillion, twenty billion, six hundred thirty-two million, six hundred fifty-four thousand, two hundred one".
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