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13021000299977 is a prime number
BaseRepresentation
bin1011110101111011000000…
…0110001111010111001001
31201002210110220021022010112
42331132300012033113021
53201314002034044402
643405433121524105
72512510345245635
oct275366006172711
951083426238115
1013021000299977
1141701a2237a0a
1215636827a3635
13735b4b676917
143303110d5dc5
15178a8d142e52
hexbd7b018f5c9

13021000299977 has 2 divisors, whose sum is σ = 13021000299978. Its totient is φ = 13021000299976.

The previous prime is 13021000299913. The next prime is 13021000300039. The reversal of 13021000299977 is 77999200012031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11925584782336 + 1095415517641 = 3453344^2 + 1046621^2 .

It is a cyclic number.

It is not a de Polignac number, because 13021000299977 - 26 = 13021000299913 is a prime.

It is a super-2 number, since 2×130210002999772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13021000299907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510500149988 + 6510500149989.

It is an arithmetic number, because the mean of its divisors is an integer number (6510500149989).

Almost surely, 213021000299977 is an apocalyptic number.

It is an amenable number.

13021000299977 is a deficient number, since it is larger than the sum of its proper divisors (1).

13021000299977 is an equidigital number, since it uses as much as digits as its factorization.

13021000299977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 428652, while the sum is 50.

The spelling of 13021000299977 in words is "thirteen trillion, twenty-one billion, two hundred ninety-nine thousand, nine hundred seventy-seven".