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1302100112 = 2481381257
BaseRepresentation
bin100110110011100…
…0111100010010000
310100202010112120002
41031213013202100
510131314200422
6333112305132
744160445145
oct11547074220
93322115502
101302100112
116090020a5
123040a21a8
131799c1b51
14c4d0a3cc
15794a7692
hex4d9c7890

1302100112 has 10 divisors (see below), whose sum is σ = 2522818998. Its totient is φ = 651050048.

The previous prime is 1302100109. The next prime is 1302100117. The reversal of 1302100112 is 2110012031.

It can be written as a sum of positive squares in only one way, i.e., 1212153856 + 89946256 = 34816^2 + 9484^2 .

It is a super-3 number, since 3×13021001123 (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1302100093 and 1302100102.

It is not an unprimeable number, because it can be changed into a prime (1302100117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40690613 + ... + 40690644.

Almost surely, 21302100112 is an apocalyptic number.

It is an amenable number.

1302100112 is a deficient number, since it is larger than the sum of its proper divisors (1220718886).

1302100112 is an equidigital number, since it uses as much as digits as its factorization.

1302100112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81381265 (or 81381259 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1302100112 is about 36084.6243156278. The cubic root of 1302100112 is about 1091.9802713052.

Adding to 1302100112 its reverse (2110012031), we get a palindrome (3412112143).

The spelling of 1302100112 in words is "one billion, three hundred two million, one hundred thousand, one hundred twelve".

Divisors: 1 2 4 8 16 81381257 162762514 325525028 651050056 1302100112