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130210032333 = 343403344111
BaseRepresentation
bin111100101000100011…
…1110110101011001101
3110110002120010222211010
41321101013312223031
54113132232013313
6135452340515433
712256504004343
oct1712107665315
9413076128733
10130210032333
1150249194577
122129b0abb79
13c381562314
14643333d993
1535c15004c3
hex1e511f6acd

130210032333 has 4 divisors (see below), whose sum is σ = 173613376448. Its totient is φ = 86806688220.

The previous prime is 130210032301. The next prime is 130210032353. The reversal of 130210032333 is 333230012031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 130210032333 - 25 = 130210032301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130210032353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21701672053 + ... + 21701672058.

It is an arithmetic number, because the mean of its divisors is an integer number (43403344112).

Almost surely, 2130210032333 is an apocalyptic number.

It is an amenable number.

130210032333 is a deficient number, since it is larger than the sum of its proper divisors (43403344115).

130210032333 is an equidigital number, since it uses as much as digits as its factorization.

130210032333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43403344114.

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 130210032333 its reverse (333230012031), we get a palindrome (463440044364).

The spelling of 130210032333 in words is "one hundred thirty billion, two hundred ten million, thirty-two thousand, three hundred thirty-three".

Divisors: 1 3 43403344111 130210032333