Base | Representation |
---|---|
bin | 111100101000100100… |
… | …1011011010010101001 |
3 | 110110002120220221010222 |
4 | 1321101021123102221 |
5 | 4113132333210312 |
6 | 135452353415425 |
7 | 12256510342022 |
oct | 1712111332251 |
9 | 413076827128 |
10 | 130210444457 |
11 | 50249446175 |
12 | 2129b26a575 |
13 | c381677a92 |
14 | 6433409c49 |
15 | 35c1582672 |
hex | 1e5125b4a9 |
130210444457 has 2 divisors, whose sum is σ = 130210444458. Its totient is φ = 130210444456.
The previous prime is 130210444439. The next prime is 130210444531. The reversal of 130210444457 is 754444012031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70743232576 + 59467211881 = 265976^2 + 243859^2 .
It is an emirp because it is prime and its reverse (754444012031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130210444457 - 212 = 130210440361 is a prime.
It is not a weakly prime, because it can be changed into another prime (130210441457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65105222228 + 65105222229.
It is an arithmetic number, because the mean of its divisors is an integer number (65105222229).
Almost surely, 2130210444457 is an apocalyptic number.
It is an amenable number.
130210444457 is a deficient number, since it is larger than the sum of its proper divisors (1).
130210444457 is an equidigital number, since it uses as much as digits as its factorization.
130210444457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 53760, while the sum is 35.
Adding to 130210444457 its reverse (754444012031), we get a palindrome (884654456488).
The spelling of 130210444457 in words is "one hundred thirty billion, two hundred ten million, four hundred forty-four thousand, four hundred fifty-seven".
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