Base | Representation |
---|---|
bin | 1011110101111011011001… |
… | …0011000000111111101111 |
3 | 1201002210202010222200012220 |
4 | 2331132312103000333233 |
5 | 3201314210200443203 |
6 | 43405451315130423 |
7 | 2512513050321603 |
oct | 275366623007757 |
9 | 51083663880186 |
10 | 13021104312303 |
11 | 4170245a19a0a |
12 | 15636b15a3a13 |
13 | 735b67093789 |
14 | 330320c4d503 |
15 | 178a9733b653 |
hex | bd7b64c0fef |
13021104312303 has 4 divisors (see below), whose sum is σ = 17361472416408. Its totient is φ = 8680736208200.
The previous prime is 13021104312233. The next prime is 13021104312319. The reversal of 13021104312303 is 30321340112031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13021104312303 - 222 = 13021100117999 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13021104312353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170184052048 + ... + 2170184052053.
It is an arithmetic number, because the mean of its divisors is an integer number (4340368104102).
Almost surely, 213021104312303 is an apocalyptic number.
13021104312303 is a deficient number, since it is larger than the sum of its proper divisors (4340368104105).
13021104312303 is an equidigital number, since it uses as much as digits as its factorization.
13021104312303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4340368104104.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13021104312303 its reverse (30321340112031), we get a palindrome (43342444424334).
The spelling of 13021104312303 in words is "thirteen trillion, twenty-one billion, one hundred four million, three hundred twelve thousand, three hundred three".
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