Base | Representation |
---|---|
bin | 10010111100101011111… |
… | …100101100000110001010 |
3 | 11121110222110020112000121 |
4 | 102330223330230012022 |
5 | 132313211234421414 |
6 | 2434103204053454 |
7 | 163034362645063 |
oct | 22745374540612 |
9 | 4543873215017 |
10 | 1302112420234 |
11 | 46224a57383a |
12 | 19043699428a |
13 | 95a33943642 |
14 | 47045d4956a |
15 | 23d0e5e2724 |
hex | 12f2bf2c18a |
1302112420234 has 4 divisors (see below), whose sum is σ = 1953168630354. Its totient is φ = 651056210116.
The previous prime is 1302112420187. The next prime is 1302112420253. The reversal of 1302112420234 is 4320242112031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1232661724009 + 69450696225 = 1110253^2 + 263535^2 .
It is a super-2 number, since 2×13021124202342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1302112420199 and 1302112420208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325528105057 + ... + 325528105060.
Almost surely, 21302112420234 is an apocalyptic number.
1302112420234 is a deficient number, since it is larger than the sum of its proper divisors (651056210120).
1302112420234 is an equidigital number, since it uses as much as digits as its factorization.
1302112420234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 651056210119.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1302112420234 its reverse (4320242112031), we get a palindrome (5622354532265).
The spelling of 1302112420234 in words is "one trillion, three hundred two billion, one hundred twelve million, four hundred twenty thousand, two hundred thirty-four".
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