| Base | Representation |
|---|---|
| bin | 111100101000100110… |
| … | …0110100010000000000 |
| 3 | 110110002122121002011102 |
| 4 | 1321101030310100000 |
| 5 | 4113133100124440 |
| 6 | 135452424433532 |
| 7 | 12256521032621 |
| oct | 1712114642000 |
| 9 | 413078532142 |
| 10 | 130211333120 |
| 11 | 502499a2900 |
| 12 | 2129b6188a8 |
| 13 | c3818c940b |
| 14 | 643359ba48 |
| 15 | 35c16aab15 |
| hex | 1e51334400 |
130211333120 has 264 divisors, whose sum is σ = 346897868184. Its totient is φ = 46858240000.
The previous prime is 130211333099. The next prime is 130211333149. The reversal of 130211333120 is 21333112031.
It can be written as a sum of positive squares in 4 ways, for example, as 35996713984 + 94214619136 = 189728^2 + 306944^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 130211333092 and 130211333101.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 62570480 + ... + 62572560.
Almost surely, 2130211333120 is an apocalyptic number.
130211333120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130211333120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173448934092).
130211333120 is an abundant number, since it is smaller than the sum of its proper divisors (216686535064).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130211333120 is a wasteful number, since it uses less digits than its factorization.
130211333120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2229 (or 2200 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 130211333120 its reverse (21333112031), we get a palindrome (151544445151).
Subtracting from 130211333120 its reverse (21333112031), we obtain a square (108878221089 = 3299672).
The spelling of 130211333120 in words is "one hundred thirty billion, two hundred eleven million, three hundred thirty-three thousand, one hundred twenty".
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