130212013433 has 2 divisors, whose sum is σ = 130212013434. Its totient is φ = 130212013432.

The previous prime is 130212013423. The next prime is 130212013457. The reversal of 130212013433 is 334310212031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65519617024 + 64692396409 = 255968^2 + 254347^2 .

It is a cyclic number.

It is not a de Polignac number, because 130212013433 - 2⁸ = 130212013177 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130212013399 and 130212013408.

It is not a weakly prime, because it can be changed into another prime (130212013423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106006716 + 65106006717.

It is an arithmetic number, because the mean of its divisors is an integer number (65106006717).

Almost surely, 2^130212013433 is an apocalyptic number.

It is an amenable number.

130212013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130212013433 is an equidigital number, since it uses as much as digits as its factorization.

130212013433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130212013433 its reverse (334310212031), we get a palindrome (464522225464).

The spelling of 130212013433 in words is "one hundred thirty billion, two hundred twelve million, thirteen thousand, four hundred thirty-three".