Base | Representation |
---|---|
bin | 1011110101111011110101… |
… | …0000100110100000000000 |
3 | 1201002211001021210010020220 |
4 | 2331132331100212200000 |
5 | 3201314430101320000 |
6 | 43405511050503040 |
7 | 2512515666216042 |
oct | 275367520464000 |
9 | 51084037703226 |
10 | 13021221120000 |
11 | 41702a59502a5 |
12 | 1563724734a80 |
13 | 735b85340662 |
14 | 330332577a92 |
15 | 178aa27111a0 |
hex | bd7bd426800 |
13021221120000 has 480 divisors, whose sum is σ = 43500671454240. Its totient is φ = 3462635520000.
The previous prime is 13021221119887. The next prime is 13021221120073. The reversal of 13021221120000 is 2112212031.
It is a tau number, because it is divible by the number of its divisors (480).
It is a super-3 number, since 3×130212211200003 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1432315455 + ... + 1432324545.
It is an arithmetic number, because the mean of its divisors is an integer number (90626398863).
Almost surely, 213021221120000 is an apocalyptic number.
13021221120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13021221120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21750335727120).
13021221120000 is an abundant number, since it is smaller than the sum of its proper divisors (30479450334240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13021221120000 is an frugal number, since it uses more digits than its factorization.
13021221120000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9509 (or 9474 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 13021221120000 its reverse (2112212031), we get a palindrome (13023333332031).
The spelling of 13021221120000 in words is "thirteen trillion, twenty-one billion, two hundred twenty-one million, one hundred twenty thousand".
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