130213100113 has 2 divisors, whose sum is σ = 130213100114. Its totient is φ = 130213100112.

The previous prime is 130213100099. The next prime is 130213100119. The reversal of 130213100113 is 311001312031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121310800209 + 8902299904 = 348297^2 + 94352^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130213100113 is a prime.

It is a super-2 number, since 2×130213100113² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130213100119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106550056 + 65106550057.

It is an arithmetic number, because the mean of its divisors is an integer number (65106550057).

Almost surely, 2^130213100113 is an apocalyptic number.

It is an amenable number.

130213100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

130213100113 is an equidigital number, since it uses as much as digits as its factorization.

130213100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130213100113 its reverse (311001312031), we get a palindrome (441214412144).

The spelling of 130213100113 in words is "one hundred thirty billion, two hundred thirteen million, one hundred thousand, one hundred thirteen".