13021311113 has 2 divisors, whose sum is σ = 13021311114. Its totient is φ = 13021311112.

The previous prime is 13021311101. The next prime is 13021311119. The reversal of 13021311113 is 31111312031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7404258304 + 5617052809 = 86048^2 + 74947^2 .

It is a cyclic number.

It is not a de Polignac number, because 13021311113 - 2⁸ = 13021310857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13021311091 and 13021311100.

It is not a weakly prime, because it can be changed into another prime (13021311119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6510655556 + 6510655557.

It is an arithmetic number, because the mean of its divisors is an integer number (6510655557).

Almost surely, 2^13021311113 is an apocalyptic number.

It is an amenable number.

13021311113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13021311113 is an equidigital number, since it uses as much as digits as its factorization.

13021311113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13021311113 its reverse (31111312031), we get a palindrome (44132623144).

The spelling of 13021311113 in words is "thirteen billion, twenty-one million, three hundred eleven thousand, one hundred thirteen".