Search a number
-
+
1302131200000 = 21255234423
BaseRepresentation
bin10010111100101101000…
…100010101000000000000
311121111000202120122000111
4102330231010111000000
5132313231041400000
62434105114401104
7163035011402431
oct22745504250000
94544022518014
101302131200000
1146225a130304
12190441130194
1395a377ba527
1447048637488
1523d110a1cba
hex12f2d115000

1302131200000 has 312 divisors, whose sum is σ = 3396999828096. Its totient is φ = 498094080000.

The previous prime is 1302131199991. The next prime is 1302131200021. The reversal of 1302131200000 is 21312031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 294397789 + ... + 294402211.

Almost surely, 21302131200000 is an apocalyptic number.

1302131200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1302131200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1698499914048).

1302131200000 is an abundant number, since it is smaller than the sum of its proper divisors (2094868628096).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1302131200000 is an frugal number, since it uses more digits than its factorization.

1302131200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4495 (or 4453 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 1302131200000 its reverse (21312031), we get a palindrome (1302152512031).

The spelling of 1302131200000 in words is "one trillion, three hundred two billion, one hundred thirty-one million, two hundred thousand".