Search a number
-
+
1302142019 is a prime number
BaseRepresentation
bin100110110011101…
…0001110001000011
310100202012200001012
41031213101301003
510131322021034
6333113231135
744161011263
oct11547216103
93322180035
101302142019
11609030632
123041024ab
13179a07c49
14c4d1b7a3
15794b4cce
hex4d9d1c43

1302142019 has 2 divisors, whose sum is σ = 1302142020. Its totient is φ = 1302142018.

The previous prime is 1302141989. The next prime is 1302142063. The reversal of 1302142019 is 9102412031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1302142019 is a prime.

It is a super-2 number, since 2×13021420192 = 3391147675290792722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1302141985 and 1302142003.

It is not a weakly prime, because it can be changed into another prime (1302142519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651071009 + 651071010.

It is an arithmetic number, because the mean of its divisors is an integer number (651071010).

Almost surely, 21302142019 is an apocalyptic number.

1302142019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302142019 is an equidigital number, since it uses as much as digits as its factorization.

1302142019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

The square root of 1302142019 is about 36085.2049876400. The cubic root of 1302142019 is about 1091.9919860025.

The spelling of 1302142019 in words is "one billion, three hundred two million, one hundred forty-two thousand, nineteen".